Asked by Jenna
A student measured 15s for the 20 complete oscillations for an object of 200g attached at the free end of a spring. Calculate the period of oscillation (T) and the spring constant (k).
My work (just wanted to ask for opinions if this is right):
T = 2π√(m/k)
T = 20 oscillation/15 seconds = 1.33 s for 1 oscillation
1.33 = 2π√(0.2 kg/k)
k = 0.0456 N/kg
T = 1.33, k = 0.0456 N/kg
Thanks in advance for any replies.
My work (just wanted to ask for opinions if this is right):
T = 2π√(m/k)
T = 20 oscillation/15 seconds = 1.33 s for 1 oscillation
1.33 = 2π√(0.2 kg/k)
k = 0.0456 N/kg
T = 1.33, k = 0.0456 N/kg
Thanks in advance for any replies.
Answers
Answered by
bobpursley
where did you get period as 1.33 seconds?
15sec/20=.75 sec= period
it is 1.33 oscillation per second...= frequency...
15sec/20=.75 sec= period
it is 1.33 oscillation per second...= frequency...
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