Question

I've figured out the first part that the v is 1.25 m/s, but even with that knowledge can't determine how to calculate the horizontal distance. Can someone help with a formula?
You let a ball roll from rest from the top of a ramp sitting on a table. If the top of the ramp is 8 cm above the top of the table, how fast is it moving when it reaches the bottom. Assume the ball leaves the table moving horizontally with the speed 1.25 m/s. If the table is 1 m above the floor, what is the horizontal distance the ball travels before it hits the floor?

Answer 1

Ok, figure the time in air...

h=1/2 g t^2
t=sqrt(2g/h)=sqrt(19.8/1)
now,horizontal distance = v*t
=1.25m/s*timeInAir

Answer 2

Thanks so much. Works perfectly!