Asked by MELISSA

Write formulas for the compounds that form from Sr and each of the following polyatomic ion: NO3 −1, SO4 −2, PO4 −3.
SR (+3 CHARGE)

NO3(-1 CHARGE)
SO4(-2 CHARGE)
PO4(-3 CHARGE)

Re posting this question. hopefully someone can help me answer this now. Please answer to this question.

Answers

Answered by DrBob222
Here is how you do a couple of them. Then you try the others.
Sr and NO3^-1
Sr is a +2 charge. There is no Sr with a +3 charge.
Sr(NO3)2. You can see Sr is +2 and 2 NO3^- is -2 so the +2 neutralizes the -2. All compounds will be zero charge and that's how you know what numbers to use for each ion. For the sulfate (SO4^2- it is SrSO4. The easy way to do this is to write the ions down like this
SrNO3. Place the +2 charge over the Sr and the -1 charge over the NO3. Now DRAW and X (mentally) with the left diagonal over the Sr at the top and the bottom of the left diagonal under the NO3^-. The right diagonal is done the same way with the top over the NO3^- and the bottom under the Sr. Move the numbers down the diagonal at the top to the bottom of THAT diagonal; i.e., the 2 moves the the bottom right (which means 2 NO3^-) and the 1 moves to the bottom left (which means 1 for Sr). Ignore the signs. You need not write the 1 (that's understood) and if the numbers you get (like SrSO4 would be Sr2(SO4)2, reduce those to the smallest numbers; i.e., 1 so SrSO4 is what you end up with. Hope this helps. I shall be happy to check your answers or answer any questions.
Answered by MELISSA
i posted my work in the original posting
Answered by DrBob222
But you know those answers are wrong. You should follow my rules above to get the correct answers.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions