Asked by Squad
For the function f(x)=3cos(2x),what is the first point where it is increasing the fastest?
Also please tell me how you know or derived that!
Thank you!!! Please answer ASAP
Also please tell me how you know or derived that!
Thank you!!! Please answer ASAP
Answers
Answered by
Steve
the slope is given by the derivative
f(x) is increasing fastest where the slope is steepest. That is, the derivative has a maximum.
Take a look at the graphs of f and f' and you will see that for this problem, f is increasing fastest when x = 3π/4
http://www.wolframalpha.com/input/?i=plot+y%3D3cos2x,+y%3D-6sin2x
f(x) is increasing fastest where the slope is steepest. That is, the derivative has a maximum.
Take a look at the graphs of f and f' and you will see that for this problem, f is increasing fastest when x = 3π/4
http://www.wolframalpha.com/input/?i=plot+y%3D3cos2x,+y%3D-6sin2x
Answered by
Squad
I have no idea what a derivative is. Im in precalculus or advamced functions. That isna calculus topic. Is there any other way to explain it? Thank you
Answered by
squad
i know you guys are busy but please
Answered by
Steve
In that case, just look at the graph. It is clear that cos(x) is steepest where it crosses the x-axis.
Without calculus, I can't think of an analytical test to prove where the slope is steepest. Are there any similar problems in your text?
Without calculus, I can't think of an analytical test to prove where the slope is steepest. Are there any similar problems in your text?
Answered by
Squad
not at all but it is on the practice exam he provided.
But your answer makes sense thank you!
But your answer makes sense thank you!
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