I just need a base to start to help teach my child:

Find the fraction:

If 1 is added to it's numerator, then it is equivalent to 1/3. And if 1 is added to it's denominator, then it is equivalent to 1/4

User Icon for Steve Steve answered
8 years ago

(n+1)/d = 1/3

n/(d+1) = 1/4

If that's too hard to work through, then just consider that

5/15 = 1/3
4/16 = 1/4

User Icon for Michelle Michelle answered
8 years ago

Manny is there a way we can speak thur email I have a question about your post.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the fraction, we can use algebraic equations. Let's assume the fraction is represented as x/y.

According to the given information, if we add 1 to the numerator, it becomes x + 1. And if we add 1 to the denominator, it becomes y + 1.

From the first condition, we have the equation: (x + 1) / y = 1/3

And from the second condition, we have the equation: x / (y + 1) = 1/4

To solve these equations simultaneously, we can use a method called cross-multiplication. Multiply the numerator on one side by the denominator on the other side, and equate the two resulting expressions.

For the first equation, (x + 1) / y = 1/3, we can cross-multiply to get:
3(x + 1) = y

For the second equation, x / (y + 1) = 1/4, cross-multiplying gives us:
4x = y + 1

Now we have a system of two equations:
3(x + 1) = y
4x = y + 1

We can solve this system of equations using various methods, such as substitution or elimination. Let's use substitution:

From the second equation, rearrange it to solve for y:
y = 4x - 1

Now substitute this value of y into the first equation:
3(x + 1) = 4x - 1

Expand the parentheses:
3x + 3 = 4x - 1

Move all the terms involving x to one side:
3 + 1 = 4x - 3x
4 = x

Now substitute this value of x back into either of the original equations to solve for y:
y = 4(4) - 1
y = 15

Therefore, the fraction is 4/15.