Asked by raghav
If
x= \frac{ \sqrt{a+2b} + \sqrt{a-2b} }{ \sqrt{a+2b} - \sqrt{a-2b} }
Show that: bx^2-ax+b=0
x= \frac{ \sqrt{a+2b} + \sqrt{a-2b} }{ \sqrt{a+2b} - \sqrt{a-2b} }
Show that: bx^2-ax+b=0
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