Asked by pooja
If alpha& beta are the zeroes of the polynomial 2x2-7x+3. Find the sum of the reciprocal of its zeroes
Answers
Answered by
Reiny
You are probably dealing with the properties of the sum and product of roots of quadratic equations.
I will use a and b instead of alpha and beta
for 2x^2 - 7x + 3 = 0
the sum of the roots
= a+b
= 7/2
product = ab
= 3/2
so the reciprocals of the roots are 1/a and 1/b
new sum = 1/a + 1/b = (a+b)/(ab)
= (7/2) / (3/2) = 7/3
new product = (1/a)(1/b) = 1/(ab)
= 2/3
new equation:
x^2 - 7/3x + 2/3 = 0
or
3x^2 - 7x + 2 = 0
looking back, looks like I could have stopped after finding the new sum
I will use a and b instead of alpha and beta
for 2x^2 - 7x + 3 = 0
the sum of the roots
= a+b
= 7/2
product = ab
= 3/2
so the reciprocals of the roots are 1/a and 1/b
new sum = 1/a + 1/b = (a+b)/(ab)
= (7/2) / (3/2) = 7/3
new product = (1/a)(1/b) = 1/(ab)
= 2/3
new equation:
x^2 - 7/3x + 2/3 = 0
or
3x^2 - 7x + 2 = 0
looking back, looks like I could have stopped after finding the new sum
Answered by
Anonymous
Ghanta
Answered by
akansha
this answer is correct.
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