Asked by Jordan
Why is I- a stronger reducing agent than F-?
Answers
Answered by
DrBob222
2F^- --> F2 + 2e -2.87
2I^- ==> I2 + 2e -0.535
But somehow I don't think this is the answer your are looking for. As to WHY the potentials are that way-- I suppose that's the nature of the beast. F^- being such a small ion isn't likely to give up electrons. Those electrons on I^- are farther out because of the size and more easily given up.
2I^- ==> I2 + 2e -0.535
But somehow I don't think this is the answer your are looking for. As to WHY the potentials are that way-- I suppose that's the nature of the beast. F^- being such a small ion isn't likely to give up electrons. Those electrons on I^- are farther out because of the size and more easily given up.
Answered by
Jordan
Interesting. Thank you.
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