Asked by Olivea
I'm not really sure on how to prove statements are right with properties as reasons. How would you solve this?
If x + c = 0, then x = -c
Statements:
1. x+c=0
2. (x+c)+(-c) = 0 + (-c)
3. x + [c+(-c)] = 0 + (-c)
4. x + 0 = 0 + (-c)
5. x = (-c)
Would 5 be the substitution property?
If x + c = 0, then x = -c
Statements:
1. x+c=0
2. (x+c)+(-c) = 0 + (-c)
3. x + [c+(-c)] = 0 + (-c)
4. x + 0 = 0 + (-c)
5. x = (-c)
Would 5 be the substitution property?
Answers
Answered by
Olivea
Does that mean 1 would be be reasoned by the substitution property?
Answered by
Anonymous
yes i think that's correct coz when we do this sum ,,,we do it in this way
x+c=0
x+c=0
-c -c (subtracting x both side)
-------
that is x=-c
x+c=0
x+c=0
-c -c (subtracting x both side)
-------
that is x=-c
Answered by
Olivea
Oh, thank you. For number 2, I originally had the definition of addition, but I was marked wrong. I'm not very sure, but wouldn't it be considered the definition of addition if you were adding (-c) to both sides? And also, in this case x+c would equal 0 so that would be the reason you are substituting 0 for x+c in number 2 as well. I don't really understand properties..
Answered by
Anonymous
yes that's it/......u got it
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.