A √(100^2+185^2+7^2) = 210.4 km
B tanθ = 7/√(100^2+185^2)
so, θ=1.9°
An airplane is flying 100 km north and 185 km west of an airport. It is flying at a height of 7 km
A) what is the straight long distance to the airport?
B) what is the angle of elevation of the airplane, from the point of view of the airport?
1 answer
2 answers