Asked by Anonymous

3×10^18 photons of a certain light radiation are found to produce 1.5 j of energy. calculate the wavelength of light radiation
Answered by Anuradha
E=nhc/lamda
>1.5= 3*10^18 * 6.626*10^-34 * 3*10^8/ lamda(wavelength)

Therefore wavelength =3.973*10^-7
Answered by Boss
What the hell is this answer kha se copy mara h yrrr
Answered by Deepanshi
E= nhc/ lambda
1.5= 3×10^18 × 6.626×10^-34 × 3×10^8 / lambda
Lambda= 9×10^26 × 6.626×10^-34
÷ 1.5
Lambda = 39.75×10^-8 = 3975 Å
Answered by Vivek sisodia
Question
Answered by Anonymous
Calculate the wavelength & the period of a blue light wit a energy 5 X 10^-19 J


Answered by PJ
E= nhc/ lambda
1.5= 3×10^18 × 6.626×10^-34 × 3×10^8 / lambda
Lambda= 9×10^26 × 6.626×10^-34
÷ 1.5
Lambda = 39.75×10^-8 = 3975 Å
Answered by Emiway Bantai
Malum_Hai_Naa
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