Asked by ED
The gas phase reaction X+Y⇄ Z is first order in Y and second order in X. If the concentration of X is double and concentration of Y is tripled. The reaction rate would be increase by a factor of:
then,
Rate= k [x]^2[y] --> k[x]^4[y}^3
is this the correct line of thought? from this rate law how would one determine the amount that the rate is increased?
then,
Rate= k [x]^2[y] --> k[x]^4[y}^3
is this the correct line of thought? from this rate law how would one determine the amount that the rate is increased?
Answers
Answered by
DrBob222
The right line of thought but you missed a turn somewhere.
That's rate = k[x]^2[y]^1, then
rate = k(2)^2(3)^1 = 12*k
That's rate = k[x]^2[y]^1, then
rate = k(2)^2(3)^1 = 12*k
Answered by
bobpursley
rate=k [x]^2[y]
if you double x, then rate factor goes up by 4, and triple y, up by 3
overall, the rate has increased by 12
No your line of thought is nor correct.
if you double x, then rate factor goes up by 4, and triple y, up by 3
overall, the rate has increased by 12
No your line of thought is nor correct.
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