Asked by liliy

Explain why any even root of a negative number is not a real number, but an odd root of a negative number is a real number.

Answers

Answered by bobpursley
let i=sqrt(-1)
then i^2= real number
i^3= realnumber*sqrt(-1)
and so on i^2n always real
and i^3n always has sqrt(-1) as a factor
Answered by Scott
a negative number, multiplied an odd number of times, is still negative

no real number, multiplied an even number of times, can be still negative

pos times pos is pos
neg times neg is pos
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions