Asked by liliy
Explain why any even root of a negative number is not a real number, but an odd root of a negative number is a real number.
Answers
Answered by
bobpursley
let i=sqrt(-1)
then i^2= real number
i^3= realnumber*sqrt(-1)
and so on i^2n always real
and i^3n always has sqrt(-1) as a factor
then i^2= real number
i^3= realnumber*sqrt(-1)
and so on i^2n always real
and i^3n always has sqrt(-1) as a factor
Answered by
Scott
a negative number, multiplied an odd number of times, is still negative
no real number, multiplied an even number of times, can be still negative
pos times pos is pos
neg times neg is pos
no real number, multiplied an even number of times, can be still negative
pos times pos is pos
neg times neg is pos
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