wouldn't it depend on where the car was when the light turned green?
Assuming...the car was at the greenlight...
distancecar=10t
distancescooter=1/2 *2*t^2
the distances are equal, so
10=t
so you can compute distance with that time.
When the traffic light turns green, a scooter moves with constant acceleration of 2 ms–2. At same time, a car moving with constant speed of 10 m/s overtakes it. How far beyond the starting point, will the car overtake the scooter?
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