Asked by Shubham
The angles of a quadrilateral are in the ratio 2:3:7. The mean of these angle is 64. Find all the four angles?
Answers
Answered by
Reiny
Did you mean that 3 of the angles are in the ratio of 2:3:7 ?
let those three angles be 2x, 3x, and 7x
let the fourth angle be y
2x + 3x + 7x + y = 360
y + 12x = 360
y = 360 - 12x
"the mean of these angles is 64"
I will assume you mean the mean of the 3 angles.
12x/3 = 64
4x = 64
x = 16
then y = 360-192 = 168
the 4 angles are : 32° , 48°, 112°, and 168°
let those three angles be 2x, 3x, and 7x
let the fourth angle be y
2x + 3x + 7x + y = 360
y + 12x = 360
y = 360 - 12x
"the mean of these angles is 64"
I will assume you mean the mean of the 3 angles.
12x/3 = 64
4x = 64
x = 16
then y = 360-192 = 168
the 4 angles are : 32° , 48°, 112°, and 168°
Answered by
nnnnn
i didnt understand
Answered by
dritha
2x + 3x + 7x + y = 360
y + 12x = 360
y = 360 - 12x
The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers
2x + 3x + 7x = 12x
2x + 3x + 7x = 3
12x/3 = 64
4x = 64
x = 64/4
= 16
y = 360 - 12x
= 360 - (12x16)
=360 - 192
= 168
<1 = 2x = 2 x 16 = 32
<2 = 3x = 3 x 16 = 48
<3 = 7x = 7 x 16 = 112
<4 = 168 (proved above)
so the 4 <s are 32^, 48^, 112^ and 168^
y + 12x = 360
y = 360 - 12x
The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers
2x + 3x + 7x = 12x
2x + 3x + 7x = 3
12x/3 = 64
4x = 64
x = 64/4
= 16
y = 360 - 12x
= 360 - (12x16)
=360 - 192
= 168
<1 = 2x = 2 x 16 = 32
<2 = 3x = 3 x 16 = 48
<3 = 7x = 7 x 16 = 112
<4 = 168 (proved above)
so the 4 <s are 32^, 48^, 112^ and 168^
Answered by
Smartest
Useless
Answered by
Yash
Three angles of a quadrilateral are in the ratio 2:3:7.The mean of these angels is 64 degrees. Find all the four angles?
Answered by
Pro genius
Answer is 32,48,112,168
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