Asked by Jams
Find the point(s) of intersection between the following:
x^2 + y^2 = 25
3x + 4y = 0
x^2 + y^2 = 25
3x + 4y = 0
Answers
Answered by
Steve
you know that 4y = -3x, so use that in
16x^2 + 16y^2 = 400
16x^2 + (4y)^2 = 400
16x^2 + 9x^2 = 400
and I think you can take it from there, right?
16x^2 + 16y^2 = 400
16x^2 + (4y)^2 = 400
16x^2 + 9x^2 = 400
and I think you can take it from there, right?
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