A aeroplane with a mass of 9940 kg completes a vertical loop of radius 596m with a speed of 155m/s. What normal force does the airplane seat exert on the 92 kg pilot at the top of the loop and at the bottom of the loop?

Answer 1

Centripetal force = M v^2/R = Weight +/- (seat force)

A + sign applies at the top of the loop and a minus sign applies at the bottom.

The weight is M g. M is the pilot's mass. The airplane's mass does not matter. Solve for the seat force

Answer 2

Thank you for giving both speed and radius this time:

Ac = v^2/r

at the top
force on seat = m (v^2/r - g)
= 92 (155^2/596 -9.8)
= 2806 N

at the bottom
m (v^2/r + g)
=92 (155^2/596 +9.8) = 4610 N