Asked by tish
In a course a student's final exam is weighted as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?
Answers
Answered by
Steve
since they are of equal weight, their average is just the arithmetic average of the two scores: 87
Why do I suspect that the problem was misstated?
Why do I suspect that the problem was misstated?
Answered by
Ms. Sue
(84 + 90) / 2 = ?
Answered by
Unown
The final exam is weighed the same as the mid term exam. Therefore, you can add the two numbers and divide by 2.
84 + 90 = 174
174/2 = 87 (answer).
84 + 90 = 174
174/2 = 87 (answer).
Answered by
tish
In a course a student's final exam is weighted twice as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?
as final exam is weighted twice then
84*2=168
then 168+90=258
the average
258/3=86...is the ans right?
as final exam is weighted twice then
84*2=168
then 168+90=258
the average
258/3=86...is the ans right?
Answered by
Steve
that looks better.
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