Question
At equilibrium, a solution of formic acid at 25°C has a pH of 2.18. The pKa of formic acid, HCOOH, is 3.74. Which of the following is the initial concentration of the solution?
Not sure what to do my thoughts:
use henderson hasselback equation
pH = pKa + log [conj base/acid]
use the provided pH to find [H+]
use an ICE table
Im not really sure
------
from what i have done i have been able to work out all the parts of the henderson hassel back but i don't know how to find the initial concentration of the entire solution.
Not sure what to do my thoughts:
use henderson hasselback equation
pH = pKa + log [conj base/acid]
use the provided pH to find [H+]
use an ICE table
Im not really sure
------
from what i have done i have been able to work out all the parts of the henderson hassel back but i don't know how to find the initial concentration of the entire solution.
Answers
This is not a buffer problem; therefore, the HH equation is not applicable.
......HCOOH ==> H^+ + HCOO^-
I......Y........0......0
C......-x.......x......x
E.....Y-x.......x......x
You know pKa, convert that to Ka.
Ka = (H^+)(HCOO^-)/(HCOOH)
The problem gives you pH so you know (H^+) = (HCOO^-) = x.
Substitute that into the Ka expression and solve for Y
......HCOOH ==> H^+ + HCOO^-
I......Y........0......0
C......-x.......x......x
E.....Y-x.......x......x
You know pKa, convert that to Ka.
Ka = (H^+)(HCOO^-)/(HCOOH)
The problem gives you pH so you know (H^+) = (HCOO^-) = x.
Substitute that into the Ka expression and solve for Y
thank you! :)
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