Asked by liliy
2x/x-5 + 1/x-1=0
Answers
Answered by
Reiny
I am sure you meant:
2x/(x-5) + 1/(x-1) = 0
multiply each of the three terms by (x-5)(x-1) , the LCD
2x(x-1) + 1(x-5) = 0
2x^2 - 2x + x - 5 = 0
2x^2 - x - 5 = 0
x = (1 ± √41)/4
the way you have it, it would be
2 - 5 + 1/x - 1 0
1/x = 4
x = 1/4
2x/(x-5) + 1/(x-1) = 0
multiply each of the three terms by (x-5)(x-1) , the LCD
2x(x-1) + 1(x-5) = 0
2x^2 - 2x + x - 5 = 0
2x^2 - x - 5 = 0
x = (1 ± √41)/4
the way you have it, it would be
2 - 5 + 1/x - 1 0
1/x = 4
x = 1/4
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