Asked by norest
Forces of 23 N and 41 N act at a point and are inclined at 90° to each other. Find, by drawing, the resultant force and its direction relative to the 41 N force.
Answers
Answered by
bobpursley
Draw the triangle
force=sqrt(23^2+41^2)
angle=arctan(23/41)
force=sqrt(23^2+41^2)
angle=arctan(23/41)
Answered by
Steve
the resultant has magnitude
√(23^2 + 41^2)
and direction θ where
tanθ = 23/41
√(23^2 + 41^2)
and direction θ where
tanθ = 23/41
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