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98.4 * (1/2)^(19/3.8) = 3.075 g

CH3COOH***
H2PO4^–
LiOH
NH3

2 answers

Ignore the numbers haha. the question is "Which of the following is an Arrhenius base" My computer glitched and mixed up the question
I believe the original definition for an Arrhenius base was that a base material contained the OH ion. LiOH would be the answer for this question. I believe the definition was expanded somewhat, later, to include anything that produced an OH ion in aqueous solution. As such, NH3 would qualify because
NH3 + HOH ==> NH4^+ + OH^-
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