Consider the 50.0-kg mountain climber in
the figure to the right. Find (a) the tension
in the rope and (b) the force that the
mountain climber must exert with her feet
on the vertical rock face to remain
stationary. Assume that the force is exerted
parallel to her legs. Also, assume negligible
force exerted by her arms. (c) What is the minimum coefficient of friction between her shoes and the cliff.
I have managed to find part a using mgsin/cos(theta) the square root of those products squared. I ended up with 490N here.
Why does this process not work for the second force with the legs against the wall? And how do you find the coefficient from there?
1 answer
All I see to the right is an ad.
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