Asked by Eze GDSS

half of the sum of two number is 7,while one third of their product is 16,find the numbers

9 years ago

Answered by Steve

(x+y)/2 = 7
xy/3 = 16

y=48/x

x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) = 0

x and y are 6 and 8

9 years ago

Answered by Praise

Thanks

5 years ago

Answered by Anonymous

Not great

5 years ago

Answered by Preddy

x+y)/2 = 7
xy/3 = 16

y=48/x

x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) =0
The numbers are 6 and 8
That's all

5 years ago

Answered by Musa

thanks for solving my question

4 years ago

Answered by BENEFIT

1.A ,2.B

3 years ago

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