Asked by Anshika
the sum of two numbers is 14 & sum of it's reciprocal is 7/20.Find the numbers?
Answers
Answered by
Steve
x+y = 14
1/x + 1/y = 7/20
Now just crank it out.
1/x + 1/y = 7/20
Now just crank it out.
Answered by
Reiny
from Steve's ...
1/x + 1/y = 7/20
times 20xy, the LCD
20y + 20x = 7xy
20(y+x) = 7xy
20(14) = 7xy
40 = xy -----> y = 40/x
plug into the first:
x + 40/x = 14
x^2 + 40 - 14x = 0
(x-10)(x-4) = 0
x = 10 or x = 4
if x = 10, y = 40/10 = 4
if x = 4 , y = 40/4 = 10
the numbers are 10 and 4
1/x + 1/y = 7/20
times 20xy, the LCD
20y + 20x = 7xy
20(y+x) = 7xy
20(14) = 7xy
40 = xy -----> y = 40/x
plug into the first:
x + 40/x = 14
x^2 + 40 - 14x = 0
(x-10)(x-4) = 0
x = 10 or x = 4
if x = 10, y = 40/10 = 4
if x = 4 , y = 40/4 = 10
the numbers are 10 and 4
Answered by
Reiny
When I answered this question there was another solution after Steve's which has now been deleted.
I only completed Steve's solution to correct that other posting.
I only completed Steve's solution to correct that other posting.
Answered by
muskan
let x be a number,then 1\x is its reciprocal
A.Q
=x+1\x=7\20
14+1/x=7/20
280x + 20 =7x
280x + 20 - 7x = 0
hence ,answer completed í ½í¸í ½í¸
A.Q
=x+1\x=7\20
14+1/x=7/20
280x + 20 =7x
280x + 20 - 7x = 0
hence ,answer completed í ½í¸í ½í¸
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