Asked by yash sharma

A scooter acquires a velocity of 30km/hr in 10 seconds just after the start.it takes 20 seconds to stop.calculate the acceleration in the two cases
Answered by Steve
start: a = v/t = 30km/hr/10s = 3km/hr/s

If you like, you can convert km/hr to m/s and your answer will be the usual m/s^2.

since it takes twice as long to stop, the acceleration is half as much. And negative.
Answered by Charu
In 1st case
v=10m/s
u=0m/s
t=10sec

equation= v=u+at
10=0+a(10)
10=a(10)
a=10/10
a=1m/s

In 2nd case
v=0m/s
u=10m/s
t=20sec

equation will be same v=u+at
0=10+a(20)
-10=a(20)
a=-10/20
a=-0.5m/s
Answered by Anonymous
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Answered by Bhumika singh
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Answered by Rishi
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Answered by Anonymous
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Answered by Bhavya
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Answered by Rani
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