Asked by joe
A dolphin wants to swim directly back to its home bay, which is 0.800 km due west. It can swim at a speed of 3.58 m/s relative to the water, but a uniform water current flows with speed 2.95 m/s in the southeast direction.
Answers
Answered by
bobpursley
draw the diagram. t is time swimming
2.95*t*sin135S + 2.95tcos(135)E+3.58tSinTheta N+3.56tCosTheta W = 800W
Now looking at NS only
2.95*t*sin135S +3.58tSinTheta N=0
t divides out, so
Theta= arcsin 2.95/3.58= 180+55.5 deg, that is the direction he has to swim. Now, how long? Look in the EW direction.
2.95tcos(135)E+ 3.56tCosTheta W = 800W
time=800/(2.95 cos(135) - 3.56 Cos55.5)=11317 sec which is a long time.
check my math.
2.95*t*sin135S + 2.95tcos(135)E+3.58tSinTheta N+3.56tCosTheta W = 800W
Now looking at NS only
2.95*t*sin135S +3.58tSinTheta N=0
t divides out, so
Theta= arcsin 2.95/3.58= 180+55.5 deg, that is the direction he has to swim. Now, how long? Look in the EW direction.
2.95tcos(135)E+ 3.56tCosTheta W = 800W
time=800/(2.95 cos(135) - 3.56 Cos55.5)=11317 sec which is a long time.
check my math.
Answered by
wagari
an inclimed plane rises to a height of 2 m over a distance of 6m calculate:the angle of the slope?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.