Asked by CHRISTINE
A ball is dropped onto the floor from a height of 20m. It rebounds to a height of 15m. If the ball was in contact with the floor for 0.01sec what was its average acceleration during the contact take g=10m/s
Answers
Answered by
Scott
downward velocity at impact
... v = √(2 * 10 * 20) = 20 m/s
upward velocity after impact
... v = √(2 * 10 * 15) = 10√3 m/s
accel = Δv / t = (20 + 10√3) / .01
...units are m/s²
... v = √(2 * 10 * 20) = 20 m/s
upward velocity after impact
... v = √(2 * 10 * 15) = 10√3 m/s
accel = Δv / t = (20 + 10√3) / .01
...units are m/s²
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