Asked by Linda
Find an equation of the tangent line to the curve
2(x2+y2)2=25(x2−y2)
(a lemniscate) at the point (3,1). Please help.
2(x2+y2)2=25(x2−y2)
(a lemniscate) at the point (3,1). Please help.
Answers
Answered by
bobpursley
take the derivative...
2(x^2+y^2+2xy)=25(x^2-y^2)
2(2x dx + 2ydy+2ydx+2xdy=25(2xdx-2ydy)
collect the dy terms
dy(4y+2x-50y)=dx(-4x-2y+50x)
dy/dx= you do it, then put in the point 3,1 and solve for dy/dx
2(x^2+y^2+2xy)=25(x^2-y^2)
2(2x dx + 2ydy+2ydx+2xdy=25(2xdx-2ydy)
collect the dy terms
dy(4y+2x-50y)=dx(-4x-2y+50x)
dy/dx= you do it, then put in the point 3,1 and solve for dy/dx
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