Asked by Kiki

Marting throws a baseball upwards at a velocity of 80 ft/sec. The following equation models this situation: H (t) = -16t squared + 80t + 6 , where H(t) is the height of the ball in feet and t is the time in seconds after the ball was released. HOW LONG WILL IT TAKE THE BALL TO REACH ITS PEAK (highest point)?

If the ball takes 2.5 secs to reach its highest point what is the maximum height the ball will travel? 102ft 106ft 2ft OR 180ft

How high will the ball hit in 4secs? 102ft 0ft -90ft OR 70ft
Answered by Reiny
Kiki, I found the 2.5 seconds for you in your previous post.
Just sub that value into your equation.

then do it again for t = 4

let me know what you got.
Answered by Kiki
Im not understanding this at all.
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