It was observed that the shadow of a vertical pole of 6 meters longer when the angle of elevation of the sun was 30° than when it was 60°.By means of a sketched diagram,calculate,correct to two decimal places,the height of the pole.

Answer 1

tan 60deg = y/x y/x =1.7325

tan 30 deg = y/(x + 6) = .577
x = shadow and y = pole

y = 1.7325x

y = .577(x +6)

Since they both equal y, you can say..

1.7325x = .577x + 3.462
Solve for x to get the shadow for the 60 degrees.

Find y, by putting this answer into both equations. If you did everything correct, you should get the same value for y. I got around 5.2 meters. See if you get the same thing.