Asked by Brittney
y^2+xy-3x=-5
dy/dt=-4
x=3
y=1
find dx/dt.
i tried doing 2y(dy/dt)+ydx/dt-3=0 but i am not getting the right answer. Please tell me where i am going wrong.
dy/dt=-4
x=3
y=1
find dx/dt.
i tried doing 2y(dy/dt)+ydx/dt-3=0 but i am not getting the right answer. Please tell me where i am going wrong.
Answers
Answered by
Reiny
your derivative is wrong, the xy needs a product rule
2y dy/dt + x dy/dt + y dx/dt - 3dx/dt = 0
plugging in our stuff
2 (-4) + 3(-4) + 1(dx/dt) - 3 dx/dt = 0
-2 dx/dt = 20
dx/dt = -10
2y dy/dt + x dy/dt + y dx/dt - 3dx/dt = 0
plugging in our stuff
2 (-4) + 3(-4) + 1(dx/dt) - 3 dx/dt = 0
-2 dx/dt = 20
dx/dt = -10
Answered by
Scott
you need to use the product rule for xy
x dy/dt + y dx/dt
x dy/dt + y dx/dt
Answered by
Brittney
Thank you for the help! Completely forgot about that rule... woops
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