USING EQUATION SHOW HOW AQUEOUS SOLUTION OF HYDROCHLORIC ACID CONTAINING HYDROXONIUM ION NEUTRALISED POTASSIUM HYDROXIDE
3 answers
KOH + HCl => KCl + H23^+
I'm guessing that the author wants this.
H3O^+(aq) + Cl^-(aq) + KOH ==> KCl(aq) + 2H2O(l)
H3O^+(aq) + Cl^-(aq) + KOH ==> KCl(aq) + 2H2O(l)
OK, that makes sense... The ionic equation.