Asked by emily
Verify that sec(θ)/csc(θ)-cot(θ) - sec(θ)/csc(θ)-cot(θ) = 2csc(θ) is an identity.
can some help me through this? thank you!
can some help me through this? thank you!
Answers
Answered by
Steve
sec(θ)/(csc(θ)-cot(θ)) - sec(θ)/(csc(θ)+cot(θ))
becomes
sec(θ)(csc(θ)+cot(θ)) - sec(θ)(csc(θ)-cot(θ))
----------------------------------------------------------
(csc(θ)-cot(θ))(csc(θ)+cot(θ))
Now expand the numerator and note that the denominator is just 1.
becomes
sec(θ)(csc(θ)+cot(θ)) - sec(θ)(csc(θ)-cot(θ))
----------------------------------------------------------
(csc(θ)-cot(θ))(csc(θ)+cot(θ))
Now expand the numerator and note that the denominator is just 1.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.