Asked by kate
how do i find the critical points of the function g(x)=xe^-x
i think the derivative is xe^-x*-x^2e???
i think the derivative is xe^-x*-x^2e???
Answers
Answered by
bobpursley
No on derivative...
f=xe^-x
f'= e^-x - xe^-x
The first term is not the same as yours.
f=xe^-x
f'= e^-x - xe^-x
The first term is not the same as yours.
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