Asked by pinky
The volume of a sphere is increased by 6% calculate the corresponding percentage increase in the area.
Answers
Answered by
Reiny
volume would be proportional to the cube of the radius
so original radius =(1.06)^(1/3)
But area is proportional to the square of the radius
so new area = ( (1.06)^(1/3) )^2
= 1.06^(2/3)
= 1.0396
so the surface area increased by appr 3.96%
so original radius =(1.06)^(1/3)
But area is proportional to the square of the radius
so new area = ( (1.06)^(1/3) )^2
= 1.06^(2/3)
= 1.0396
so the surface area increased by appr 3.96%
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