Asked by John
A skier slides down a ski slope with an acceleration 2.2 m/s^2 directed down the slope. The coefficient of kinetic friction between the skis and the slope is 0.24. What is the angle of the slope with the ground?
Answers
Answered by
Damon
friction force up slope = .24 m g cos A
gravity down slope = m g sin A
m (2.2) = m (9.81)(sin A - .24 cos A)
sin A - .24 cos A = .224
well I can make a table
A, left side
0, -.24
5, .083
10, .17
15, .254
so between 10 and 15 deg
13, .22
13 degrees is very close
try 13.2
13.2 , .224 close enough
gravity down slope = m g sin A
m (2.2) = m (9.81)(sin A - .24 cos A)
sin A - .24 cos A = .224
well I can make a table
A, left side
0, -.24
5, .083
10, .17
15, .254
so between 10 and 15 deg
13, .22
13 degrees is very close
try 13.2
13.2 , .224 close enough
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