Asked by Eve
Compute the approximate density of methane, CH4, at 20oC and 5.00 atm. The molecular weight of methane is 16.0.
Answers
Answered by
bobpursley
assume one mole (16grams)
density=mass/volume
so volume= 22.4(273+20)/273*1atm/5atm
volume=4.81 liters
denstiy=16/4.81 g/liter
density=mass/volume
so volume= 22.4(273+20)/273*1atm/5atm
volume=4.81 liters
denstiy=16/4.81 g/liter
Answered by
Eve
dude thank you so much
Answered by
Olereb48
From Ideal Gas Law PV=nRT=(mass/fwt)RT => (mass/Vol)=Density=P(fwt)/RT
P = 5 Atm
fwt = 16 g/mol
R = 0.08206 L-Atm/mol-K
T = (273+20)K = 293K
Density = [(5)(16)/(0.08206)(293)]g/L
= 3.33 g/L
P = 5 Atm
fwt = 16 g/mol
R = 0.08206 L-Atm/mol-K
T = (273+20)K = 293K
Density = [(5)(16)/(0.08206)(293)]g/L
= 3.33 g/L
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