Asked by Annie
A chemist mixed a 70% alcohol solution with a 30% alcohol solution to make a 45% alcohol solution. How many liters of each were used to make 120 L of a 45% solution?
I tried solving this with elimination method and made two separate equations. For instance,
x+y = 120(.45)
.70x+.30y=.45
This was the set up I came up with. But once I tried solving it I got an answer that I knew couldn't be right.
I tried solving this with elimination method and made two separate equations. For instance,
x+y = 120(.45)
.70x+.30y=.45
This was the set up I came up with. But once I tried solving it I got an answer that I knew couldn't be right.
Answers
Answered by
Bosnian
x = 70% alcohol solution
y = 30% alcohol solution
120 L of a 45% solution have :
120 * 0.45 = 54 L alcohol
Now you must solve system :
0.7 x + 0.3 y = 54
x + y = 120
The solutions are :
x = 45 L , y = 75 L
Proof :
0.7 * 45 + 0.3 * 75 = 31.5 + 22.5 = 54 L
x + y = 45 + 75 = 120 L
y = 30% alcohol solution
120 L of a 45% solution have :
120 * 0.45 = 54 L alcohol
Now you must solve system :
0.7 x + 0.3 y = 54
x + y = 120
The solutions are :
x = 45 L , y = 75 L
Proof :
0.7 * 45 + 0.3 * 75 = 31.5 + 22.5 = 54 L
x + y = 45 + 75 = 120 L
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