Asked by Bree

R is the first quadrant region enclosed by the x-axis, the curve y = 2x + a, and the line x = a, where a > 0. Find the value of a so that the area of the region R is 18 square units.
Answered by Steve
even without calculus, this one is easy. The x-intercept of y=2x+a is x = -a/2

So, you have a triangle with base 3a/2 and height 3a, so the area is 9a^2/4.

If 9a^2/4 = 18, a = √8

check:

∫[-a/2,a] 2x+a dx = 9a^2/4
Answered by Bree
I did a(a+2a+a)/2=18
and got 3 but idk if that's right
Answered by Bree
the answer choices are
A. 3
B. 3.772
C. 4.242
D. 9
Answered by Pizza Man
Where did steve get the triangle parts from?? :(
Answered by yikes
i have never gotten one straightforward correct answer from this guy steve
Answered by Lana
Look at the graph and you'll see the triangle and rectangle. It is baseline geometry problem. The answer is 3
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