Asked by Nicole
Find the solution to each equation.
2^x=17
4log4^(x)=7
2^x=17
4log4^(x)=7
Answers
Answered by
Reiny
2^x=17
take log of both sides, then use log rules
x log2 = log 17
x = log17/log2 = appr 4.087
4log4^(x)=7
log 4^x = 1.75
4^x = 10^1.75
4^x = 56.23413...
repeat the same steps I used in the first one to finish it
take log of both sides, then use log rules
x log2 = log 17
x = log17/log2 = appr 4.087
4log4^(x)=7
log 4^x = 1.75
4^x = 10^1.75
4^x = 56.23413...
repeat the same steps I used in the first one to finish it
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