Supposing we allow 272g of phosphorus to react with excess oxygen which forms tetraphosphorus decoxide P4O10 in 89.5% yield. In the second step reaction, a 96.8% yield of H3PO4 is obtain by reacting P4O10 with 6H2O. Work out the mass of H3PO4 obtained?
1 answer
2980g
1 answer