Asked by JCancer
What is the equation of the circle with center (-4,-3) that passes through the point (6,2)?
(x-4)2+(y-2)2=9
(x-3)2+(y+2)2=9
(x-3)2+(y+2)2=3
(x+3)2+(y-2)2=3
(x-4)2+(y-2)2=9
(x-3)2+(y+2)2=9
(x-3)2+(y+2)2=3
(x+3)2+(y-2)2=3
Answers
Answered by
Steve
the distance between those two points is √125
The equation is
(x+4)^2 + (y+3)^2 = 125
You have mangled the question somehow. None of the equations has the correct center or radius.
The equation is
(x+4)^2 + (y+3)^2 = 125
You have mangled the question somehow. None of the equations has the correct center or radius.
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