Asked by Anonymous
The students asked their math teacher to tell them her age. She didn’t want to tell them, but she replied, “If you take two years from my present age the result will be three times my son’s age, and seven years ago my age was twice what his will be in two years.” How old is the teacher?
Answers
Answered by
Reiny
teacher's age --- x
son's age ---- y
x-2 = 3y
x = 3y+2
x-7 = 2(y+2)
3y + 2 - 7 = 2y + 4
y = 9
x= 3(9)+2 = 29
son's age ---- y
x-2 = 3y
x = 3y+2
x-7 = 2(y+2)
3y + 2 - 7 = 2y + 4
y = 9
x= 3(9)+2 = 29
Answered by
Anonymous
thanks
Answered by
Betty
teacher's age --- x
son's age ---- y
x-2 = 3y
x = 3y+2
x-7 = 2(y+2)
3y + 2 - 7 = 2y + 4
y = 9
x= 3(9)+2 = 29
son's age ---- y
x-2 = 3y
x = 3y+2
x-7 = 2(y+2)
3y + 2 - 7 = 2y + 4
y = 9
x= 3(9)+2 = 29
Answered by
Claire
yess it helped
Answered by
Anonymous
So bad!
Wrong
Loser!
Just kidding. Awesome you did so well😀😀🤩🤩🤩😇
Wrong
Loser!
Just kidding. Awesome you did so well😀😀🤩🤩🤩😇
Answered by
Blank
Ur right!
Answered by
Someone
Thanks so much for your help!
Answered by
jhonny the pappaya
29
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