Asked by Catherine

A 5.000g sample of a dry mixture of potassium hydroxide, potassium carboate and potassium chloride is reacted with 0.100 L of 2.00-molar HCl solution. A 249.0 mL sample of dry carbon dioxide gas, measured at 22.0 degree Celsius and 740.0 torr, is obtained from this reaction. What was the percentage of potassium carbonate in the mixture?
Answered by DrBob222
Use PV = nRT to solve for n = mols CO2.
mols CO2 = mols K2CO3
Then grams K2CO3 = mols K2CO3 x molar mass K2CO3.
%K2CO3 = (grams K2CO3/mass sample)*100 = ?
Answered by Anonymous
27.68%
There are no AI answers yet. The ability to request AI answers is coming soon!