Asked by ali
the solubility of Mg(OH)2 at 25C is4.6x10^-3 g/100cm3? what is the solubility product of M g(OH)2?
Answers
Answered by
DrBob222
4.6E-3 g/100 cc = 4.6E-2/1000 cc.
mols = 4.6E-2/molar mass Mg(OH)2.
Then M = mols/L. I will call that S whatever it is.
........Mg(OH)2 ==> Mg^2+ + 2OH^-
I.......solid.......0........0
C.......solid.......s........2s
E.......solid.......s........2s
Substitute the E line into the Ksp expression and calculate the value of Ksp.
mols = 4.6E-2/molar mass Mg(OH)2.
Then M = mols/L. I will call that S whatever it is.
........Mg(OH)2 ==> Mg^2+ + 2OH^-
I.......solid.......0........0
C.......solid.......s........2s
E.......solid.......s........2s
Substitute the E line into the Ksp expression and calculate the value of Ksp.
Answered by
Affan
1.258
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