Question

a dad has two daughters – Wendy and Julia. Wendy is twice as old as Julia. The man is now five times as old as Wendy, and in 4 years he will be six times as old as Julia. Find the present age of the father.

Answer 1

Julia's age : a year-old
Wendy is twice the age of Julia
= > Wendy = 2a year-old
Dad's age : b year-old
" The man is now five times as old as Wendy " b / 2a = 5 <=> b = 10a
 " In four years he will be six times as old as Julia " :
( B + 4 ) / (a + 4 ) = 6 + 4 = 6. <=> b (a + 4 )
<=> B = 6a +20
I have two equations :
6a + b = 20
b = 10a
= > 10a = 6a + 20 - > a = 5
- > B = 10a = 50
father's age is 50 years old

Answer 2

Julia's age : a year-old
"Wendy is twice the age of Julia"
= > Wendy = 2a -old age
Father age : b age
" The man is now five times as old as Wendy ": b/2a = 5 <=> b = 10a
 " in 4 years he will be six times as old as Julia " :
(b + 4)/(a+ 4)=6 <=> b+4=6.(a + 4 )
<=> B = 6a +20
I have two equations :
6a + b = 20
b = 10a
= > 10a = 6a + 20 - > a = 5
- > B = 10a = 50
father's age is 50 years old

Answer 3

simpler setup:

Julia's age --- x
Wendy's age --2x
Father's age -- 10x

In 4 years from now:
Wendy --- x+4
Father --- 10x + 4

10x+4 = 6(x+4)
10x+4 = 6x+24
4x=20
x = 5

Father: 10x = 50

Answer 4

thanks soon much

Answer 5

thnks