Question

y= (1-tan x)/sec x
find dy/dx


y= (1 + tan3x) ^(3/2)
find dy/dx


thanks a lot

Answer 1

y= (1-tan x)/sec x
= (1-sinx/cosx)*cosx=cosx-sinx
y'=-sinx-cosx

y=(1+tan3x)^3/2
y'=3/2(1+tan3x)^1/2 (3sec^2 3x)

Answer 2

for the question
y= (1 + tan3x) ^(3/2)
find dy/dx

the ans is
y'=9/2(1+tan3x)^1/2 (3sec^2 3x)

Answer 3

bob is right,

mrfrank has an extra 3 hanging around

should be

(9/2)(1+tan (3x))^(1/2) (sec^2 (3x) )