Asked by Heaven
Find the exact roots of 0= x^2 -7x +7
I think you have to use the quadratic formula, but I can't figure out how to do this or how to verify. If you could show me step by step, that would be awesome. Thanks
I think you have to use the quadratic formula, but I can't figure out how to do this or how to verify. If you could show me step by step, that would be awesome. Thanks
Answers
Answered by
Reiny
Every student of mathematics must know and memorize the quadratic equation formula:
for ax^2 + bx + c = 0
x = (-b ± √(b^2 - 4ac) /(2a)
for yours:
a = 1
b = -7
c = 7
x = (7 ± √(49 - 4(1)(7))/(2
= (7 ± √21)/2
x = (7 + √21)/2 OR x = (7 - √21)/2
Since it asked for the "exact" roots, you leave the answers that way.
If you are asked to "verify" , sub those values into the original equation. I will do one of the them , you try the other
if x = (7+√21)/2
LS = [(7+√21)/2]^2 - 7(7+√21)/2 + 7
= (49 + 14√21 + 21)/4 - (49 + 7√21)/2 + 7
= (70 + 14√2 - 98 - 14√21 + 28)/4
= 0/4
= 0
= RS
so x = (7 + √21)/2
You try the 2nd root.
Notice the verification looked messier than the original solving.
=
for ax^2 + bx + c = 0
x = (-b ± √(b^2 - 4ac) /(2a)
for yours:
a = 1
b = -7
c = 7
x = (7 ± √(49 - 4(1)(7))/(2
= (7 ± √21)/2
x = (7 + √21)/2 OR x = (7 - √21)/2
Since it asked for the "exact" roots, you leave the answers that way.
If you are asked to "verify" , sub those values into the original equation. I will do one of the them , you try the other
if x = (7+√21)/2
LS = [(7+√21)/2]^2 - 7(7+√21)/2 + 7
= (49 + 14√21 + 21)/4 - (49 + 7√21)/2 + 7
= (70 + 14√2 - 98 - 14√21 + 28)/4
= 0/4
= 0
= RS
so x = (7 + √21)/2
You try the 2nd root.
Notice the verification looked messier than the original solving.
=
There are no AI answers yet. The ability to request AI answers is coming soon!