A = 3t^2 + 7
dA/dt = 6t
now plug in t=5
The area of a blot of ink is growing such that after t seconds its area is given by A=(3t square +7) cm square. Calculate the rate of increase of area at t=5 second.
4 answers
i want answer of this question
Answer is 30 cm^2
Given that
A = 3t²+ 7
Here we can find out the value of A easily if we differentiate it ,
On doing differentiation we obtain
area = dx/dt
= d ( 3t² + 7 ) / dt = 6t
we are given that t = 5
second
Now putting t = 5
A = 6 × 5
A = 30 cm²
Hope this helps you ☺
A = 3t²+ 7
Here we can find out the value of A easily if we differentiate it ,
On doing differentiation we obtain
area = dx/dt
= d ( 3t² + 7 ) / dt = 6t
we are given that t = 5
second
Now putting t = 5
A = 6 × 5
A = 30 cm²
Hope this helps you ☺